## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$\log_{10}100=2$
Since $b^y=x$ is equivalent to $y=\log_bx,$ the given equation, $10^2=100 ,$ is equivalent to \begin{array}{l}\require{cancel} \log_{10}100=2 .\end{array} Note that for $\log_{10}x$, the 10 is implied and is often written as $log(x)$.