## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$x=5$
Converting to exponential form, the given logarithmic equation, $\log_2{32}=x ,$ is equivalent to \begin{array}{l}\require{cancel} 2^x=32 \\\\ 2^x=2^5=32 .\end{array} We have now found what value x makes the above statement, $2^x=32$, true: \begin{array}{l}\require{cancel} x=5 .\end{array}