Answer
$\log_{e}20.0855=3$
Work Step by Step
Since $b^y=x$ is equivalent to $y=\log_bx,$ the given equation, $
e^3=20.0855
,$ is equivalent to
\begin{array}{l}\require{cancel}
\log_{e}20.0855=3
.\end{array}
Note that $\log_ex$ is often abreviated $ln(x)$.