## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$\log_{e}7.3891=2$
Since $b^y=x$ is equivalent to $y=\log_bx,$ the given equation, $e^2=7.3891 ,$ is equivalent to \begin{array}{l}\require{cancel} \log_{e}7.3891=2 .\end{array} Note that $\log_ex$ is often abreviated $ln(x)$.