## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$10^{0.4771}=3$
Since $y=\log_bx$ is equivalent to $b^y=x,$ the given equation, $\log_{10} 3=0.4771 ,$ is equivalent to \begin{array}{l}\require{cancel} 10^{0.4771}=3 .\end{array}