## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$\dfrac{\sqrt[]{14a}}{6}$
Rationalizing the denominator of the given expression, $\sqrt[]{\dfrac{7a}{18}} ,$ we find: \begin{array}{l}\require{cancel} \sqrt[]{\dfrac{7a}{18}\cdot\dfrac{2}{2}} \\\\= \sqrt[]{\dfrac{14a}{36}} \\\\= \dfrac{\sqrt[]{14a}}{\sqrt[]{36}} \\\\= \dfrac{\sqrt[]{14a}}{\sqrt[]{(6)^2}} \\\\= \dfrac{\sqrt[]{14a}}{6} .\end{array} * Note that it is assumed that all variables represent positive numbers.