Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 10 - Exponents and Radicals - 10.4 Dividing Radical Expressions - 10.4 Exercise Set - Page 653: 47



Work Step by Step

Rationalizing the denominator of the given expression, $ \sqrt[3]{\dfrac{5}{4}} ,$ results to \begin{array}{l}\require{cancel} \sqrt[3]{\dfrac{5}{4}\cdot\dfrac{2}{2}} \\\\= \sqrt[3]{\dfrac{10}{8}} \\\\= \dfrac{\sqrt[3]{10}}{\sqrt[3]{8}} \\\\= \dfrac{\sqrt[3]{10}}{\sqrt[3]{(2)^3}} \\\\= \dfrac{\sqrt[3]{10}}{2} .\end{array}
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