## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$\dfrac{12}{p}$
Using the properties of radicals, the given expression, $\sqrt[]{\dfrac{144}{p^2}} ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{\sqrt[]{144}}{\sqrt[]{p^2}} \\\\= \dfrac{\sqrt[]{(12)^2}}{\sqrt[]{(p)^2}} \\\\= \dfrac{12}{p} \end{array} * Note that it is assumed that all variables represent positive numbers.