## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson

# Chapter 10 - Exponents and Radicals - 10.4 Dividing Radical Expressions - 10.4 Exercise Set - Page 653: 46

#### Answer

$\dfrac{3\sqrt{35}}{14}$

#### Work Step by Step

Rationalizing the denominator of the given expression, $\dfrac{3\sqrt{5}}{2\sqrt{7}} ,$ we find: \begin{array}{l}\require{cancel} \dfrac{3\sqrt{5}}{2\sqrt{7}}\cdot\dfrac{\sqrt{7}}{\sqrt{7}} \\\\= \dfrac{3\sqrt{35}}{2\sqrt{(7)^2}} \\\\= \dfrac{3\sqrt{35}}{2\cdot7} \\\\= \dfrac{3\sqrt{35}}{14} .\end{array}

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