Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 10 - Exponents and Radicals - 10.4 Dividing Radical Expressions - 10.4 Exercise Set - Page 653: 32



Work Step by Step

Using the properties of radicals, the given expression, $ \dfrac{\sqrt[3]{35}}{\sqrt[3]{5}} ,$ simplifies to \begin{array}{l}\require{cancel} \sqrt[3]{\dfrac{35}{5}} \\\\= \sqrt[3]{7} \end{array}
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