Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 10 - Exponents and Radicals - 10.4 Dividing Radical Expressions - 10.4 Exercise Set - Page 653: 44



Work Step by Step

Rationalizing the denominator of the given expression, $ \sqrt{\dfrac{7}{2}} ,$ we find: \begin{array}{l}\require{cancel} \sqrt{\dfrac{7}{2}\cdot\dfrac{2}{2}} \\\\= \sqrt{\dfrac{14}{(2)^2}} \\\\= \dfrac{\sqrt{14}}{\sqrt{(2)^2}} \\\\= \dfrac{\sqrt{14}}{2} .\end{array}
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