Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 10 - Exponents and Radicals - 10.1 Radical Expressions and Functions - 10.1 Exercise Set: 91

Answer

$g(19)=2 ,\\\\ g(-13)=\text{does not exist} ,\\\\ g(1)=\text{does not exist} ,\\\\ g(84)=3$

Work Step by Step

$\bf{\text{Solution Outline:}}$ Substitute the given function value in $ g(t)=\sqrt[4]{t-3} .$ $\bf{\text{Solution Details:}}$ If $ t=19 ,$ then \begin{array}{l}\require{cancel} g(t)=\sqrt[4]{t-3} \\\\ g(19)=\sqrt[4]{19-3} \\\\ g(19)=\sqrt[4]{16} \\\\ g(19)=2 .\end{array} If $ t=-13 ,$ then \begin{array}{l}\require{cancel} g(t)=\sqrt[4]{t-3} \\\\ g(-13)=\sqrt[4]{-13-3} \\\\ g(-13)=\sqrt[4]{-16} \text{ (not a real number)} .\end{array} If $ t=1 ,$ then \begin{array}{l}\require{cancel} g(t)=\sqrt[4]{t-3} \\\\ g(1)=\sqrt[4]{1-3} \\\\ g(1)=\sqrt[4]{-2} \text{ (not a real number)} .\end{array} If $ t=84 ,$ then \begin{array}{l}\require{cancel} g(t)=\sqrt[4]{t-3} \\\\ g(84)=\sqrt[4]{84-3} \\\\ g(84)=\sqrt[4]{81} \\\\ g(84)=3 .\end{array} Hence, \begin{array}{l}\require{cancel} g(19)=2 ,\\\\ g(-13)=\text{does not exist} ,\\\\ g(1)=\text{does not exist} ,\\\\ g(84)=3 .\end{array}
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