## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson

# Chapter 10 - Exponents and Radicals - 10.1 Radical Expressions and Functions - 10.1 Exercise Set - Page 634: 75

#### Answer

$-3t$

#### Work Step by Step

Using the properties of radicals, the given expression, $-\sqrt{(3t)^2} ,$ simplifies to \begin{array}{l} -(3t) \\\\= -3t .\end{array} Note that it is assumed that no radicand was formed by raising negative quantities to even powers. Thus, absolute value bars are not necessary.

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