Answer
$g(0)=1
,\\\\
g(-62)=5
,\\\\
g(-13)=3
,\\\\
g(63)=-5$
Work Step by Step
$\bf{\text{Solution Outline:}}$
Substitute the given function value in $
g(x)=-\sqrt[3]{2x-1}
.$
$\bf{\text{Solution Details:}}$
If $
x=0
,$ then
\begin{array}{l}\require{cancel}
g(x)=-\sqrt[3]{2x-1}
\\\\
g(0)=-\sqrt[3]{2(0)-1}
\\\\
g(0)=-\sqrt[3]{-1}
\\\\
g(0)=1
.\end{array}
If $
x=-62
,$ then
\begin{array}{l}\require{cancel}
g(x)=-\sqrt[3]{2x-1}
\\\\
g(-62)=-\sqrt[3]{2(-62)-1}
\\\\
g(-62)=-\sqrt[3]{-125}
\\\\
g(-62)=-(-5)
\\\\
g(-62)=5
.\end{array}
If $
x=-13
,$ then
\begin{array}{l}\require{cancel}
g(x)=-\sqrt[3]{2x-1}
\\\\
g(-13)=-\sqrt[3]{2(-13)-1}
\\\\
g(-13)=-\sqrt[3]{-27}
\\\\
g(-13)=-(-3)
\\\\
g(-13)=3
.\end{array}
If $
x=63
,$ then
\begin{array}{l}\require{cancel}
g(x)=-\sqrt[3]{2x-1}
\\\\
g(63)=-\sqrt[3]{2(63)-1}
\\\\
g(63)=-\sqrt[3]{125}
\\\\
g(63)=-5
.\end{array}
Hence,
\begin{array}{l}\require{cancel}
g(0)=1
,\\\\
g(-62)=5
,\\\\
g(-13)=3
,\\\\
g(63)=-5
.\end{array}