Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 10 - Exponents and Radicals - 10.1 Radical Expressions and Functions - 10.1 Exercise Set: 90

Answer

$g(0)=1 ,\\\\ g(-62)=5 ,\\\\ g(-13)=3 ,\\\\ g(63)=-5$

Work Step by Step

$\bf{\text{Solution Outline:}}$ Substitute the given function value in $ g(x)=-\sqrt[3]{2x-1} .$ $\bf{\text{Solution Details:}}$ If $ x=0 ,$ then \begin{array}{l}\require{cancel} g(x)=-\sqrt[3]{2x-1} \\\\ g(0)=-\sqrt[3]{2(0)-1} \\\\ g(0)=-\sqrt[3]{-1} \\\\ g(0)=1 .\end{array} If $ x=-62 ,$ then \begin{array}{l}\require{cancel} g(x)=-\sqrt[3]{2x-1} \\\\ g(-62)=-\sqrt[3]{2(-62)-1} \\\\ g(-62)=-\sqrt[3]{-125} \\\\ g(-62)=-(-5) \\\\ g(-62)=5 .\end{array} If $ x=-13 ,$ then \begin{array}{l}\require{cancel} g(x)=-\sqrt[3]{2x-1} \\\\ g(-13)=-\sqrt[3]{2(-13)-1} \\\\ g(-13)=-\sqrt[3]{-27} \\\\ g(-13)=-(-3) \\\\ g(-13)=3 .\end{array} If $ x=63 ,$ then \begin{array}{l}\require{cancel} g(x)=-\sqrt[3]{2x-1} \\\\ g(63)=-\sqrt[3]{2(63)-1} \\\\ g(63)=-\sqrt[3]{125} \\\\ g(63)=-5 .\end{array} Hence, \begin{array}{l}\require{cancel} g(0)=1 ,\\\\ g(-62)=5 ,\\\\ g(-13)=3 ,\\\\ g(63)=-5 .\end{array}
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