Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 10 - Exponents and Radicals - 10.1 Radical Expressions and Functions - 10.1 Exercise Set - Page 634: 9



Work Step by Step

When we break the square root of 64 into its factors, we obtain: $ 8 ^2=8*8=64$. Because 64 can be simplified to $8^2$, we can simplify the problem to $(8^2)^.5$ When we simplify this further, multiplying 2 by .5, we are left with $8^1$.Therefore, the square root of 64 must equal 8.
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