## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$\{8\}$
When we break the square root of 64 into its factors, we obtain: $8 ^2=8*8=64$. Because 64 can be simplified to $8^2$, we can simplify the problem to $(8^2)^.5$ When we simplify this further, multiplying 2 by .5, we are left with $8^1$.Therefore, the square root of 64 must equal 8.