Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 10 - Exponents and Radicals - 10.1 Radical Expressions and Functions - 10.1 Exercise Set - Page 634: 34

Answer

$g(-3)=-2 ,\\\\ g(4)=-5 ,\\\\ g(-5)=-4$

Work Step by Step

$\bf{\text{Solution Outline:}}$ Substitute the given function value in $ g(x)=-\sqrt{(x+1)^2} .$ $\bf{\text{Solution Details:}}$ If $ x=-3 ,$ then \begin{array}{l}\require{cancel} g(x)=-\sqrt{(x+1)^2} \\\\ g(-3)=-\sqrt{(-3+1)^2} \\\\ g(-3)=-\sqrt{4} \\\\ g(-3)=-2 .\end{array} If $ x=4 ,$ then \begin{array}{l}\require{cancel} g(x)=-\sqrt{(x+1)^2} \\\\ g(4)=-\sqrt{(4+1)^2} \\\\ g(4)=-\sqrt{25} \\\\ g(4)=-5 .\end{array} If $ x=-5 ,$ then \begin{array}{l}\require{cancel} g(x)=-\sqrt{(x+1)^2} \\\\ g(-5)=-\sqrt{(-5+1)^2} \\\\ g(-5)=-\sqrt{16} \\\\ g(-5)=-4 .\end{array} Hence, \begin{array}{l}\require{cancel} g(-3)=-2 ,\\\\ g(4)=-5 ,\\\\ g(-5)=-4 .\end{array}
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