## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$4|t|$
Using $\sqrt{x^2}=|x|$, the given expression, $\sqrt{16t^2} ,$ simplifies to \begin{array}{l} \sqrt{(4t)^2} \\\\= |4t| \\\\= 4|t| .\end{array} Note: We have to put the variable in absolute value bars since it is being raised to an odd power.