Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 1 - Introduction to Algebraic Expressions - 1.8 Exponential Notation and Order of Operations - 1.8 Exercise Set: 77

Answer

$\dfrac{5}{6}$

Work Step by Step

Substituting $ x $ with $ 3 $ in the given expression, $ 45\div3^2x(x-1) $, then, \begin{array}{l}\require{cancel} 45\div3^2(3)(3-1) \\\\= 45\div9(3)(2) \\\\= 45\div27(2) \\\\= 45\div54 \\\\= \dfrac{\cancel{9}\cdot5}{\cancel{9}\cdot6} \\\\= \dfrac{5}{6} .\end{array}
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