Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 1 - Introduction to Algebraic Expressions - 1.8 Exponential Notation and Order of Operations - 1.8 Exercise Set: 130

Answer

$\text{undefined}$

Work Step by Step

Substituting $ x $ with $ 2 $, then the given expression, $ \dfrac{x^2+2^x}{x^2-2^x} $, evaluates to \begin{array}{l}\require{cancel} \dfrac{2^2+2^2}{2^2-2^2} \\\\= \dfrac{4+4}{4-4} \\\\= \dfrac{8}{0} \\\\= \text{undefined} .\end{array}
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