Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 1 - Introduction to Algebraic Expressions - 1.8 Exponential Notation and Order of Operations - 1.8 Exercise Set - Page 67: 107



Work Step by Step

Using $a(b+c)=ab+ac$ or the Distributive Property, the given expression, $ 12a^2-3ab+5b^2-5(-5a^2+4ab-6b^2) $, is equivalent to \begin{array}{l}\require{cancel} 12a^2-3ab+5b^2-5(-5a^2)-5(4ab)-5(-6b^2) \\\\= 12a^2-3ab+5b^2+25a^2-20ab+30b^2 .\end{array} By combining like terms, then this simplifies to \begin{array}{l}\require{cancel} (12a^2+25a^2)+(-3ab-20ab)+(5b^2+30b^2) \\\\= 37a^2-23ab+35b^2 .\end{array}
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