## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson

# Chapter 1 - Introduction to Algebraic Expressions - 1.8 Exponential Notation and Order of Operations - 1.8 Exercise Set: 82

#### Answer

$0$

#### Work Step by Step

Substituting $a$ with $-2$ in the given expression, $\dfrac{a^3-4a}{a(a-3)}$, then, \begin{array}{l}\require{cancel} \dfrac{(-2)^3-4(-2)}{-2(-2-3)} \\\\= \dfrac{-8+8}{-2(-5)} \\\\= \dfrac{0}{-2(-5)} \\\\= 0 .\end{array}

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