Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 1 - Introduction to Algebraic Expressions - 1.8 Exponential Notation and Order of Operations - 1.8 Exercise Set: 127

Answer

$0$

Work Step by Step

Substituting $ x $ with $ 3 $, then the given expression, $ [x+3(2-5x)\div7+x](x-3) $, evaluates to \begin{array}{l}\require{cancel} [x+3(2-5(3))\div7+3](3-3) \\\\= [x+3(2-5(3))\div7+3](0) \\\\= 0 .\end{array}
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