Answer
$0$
Work Step by Step
Substituting $
x
$ with $
3
$, then the given expression, $
[x+3(2-5x)\div7+x](x-3)
$, evaluates to
\begin{array}{l}\require{cancel}
[x+3(2-5(3))\div7+3](3-3)
\\\\=
[x+3(2-5(3))\div7+3](0)
\\\\=
0
.\end{array}
Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)
by Bittinger, Marvin L.; Ellenbogen, David J.; Johnson, Barbara L.
Published by
Pearson
ISBN 10:
0-32184-874-8
ISBN 13:
978-0-32184-874-1
Chapter 1 - Introduction to Algebraic Expressions - 1.8 Exponential Notation and Order of Operations - 1.8 Exercise Set - Page 67: 127
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