## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson

# Chapter 1 - Introduction to Algebraic Expressions - 1.8 Exponential Notation and Order of Operations - 1.8 Exercise Set - Page 66: 76

#### Answer

$\dfrac{1}{8}$

#### Work Step by Step

Substituting $a$ with $2$, then the given expression, $6a\div12a^3$, evaluates to \begin{array}{l}\require{cancel} 6(2)\div12(2)^3 \\\\= 12\div12(8) \\\\= \dfrac{12}{12(8)} \\\\= \dfrac{\cancel{12}}{\cancel{12}(8)} \\\\= \dfrac{1}{8} .\end{array}

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