Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 1 - Introduction to Algebraic Expressions - 1.7 Multiplication and Division of Real Numbers - 1.7 Exercise Set: 115

Answer

$1$

Work Step by Step

The given expression, $ -\dfrac{5}{9}\div\left( -\dfrac{5}{9} \right) $, simplifies to \begin{array}{l}\require{cancel} -\dfrac{5}{9}\cdot\left( -\dfrac{9}{5} \right) \\\\= \dfrac{-5(-9)}{9(5)} \\\\= \dfrac{45}{45} \\\\= 1 .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.