Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 1 - Introduction to Algebraic Expressions - 1.7 Multiplication and Division of Real Numbers - 1.7 Exercise Set - Page 58: 64

Answer

$7$

Work Step by Step

The given expression, $ -63\div(-9) $, simplifies to \begin{array}{l}\require{cancel} \dfrac{-63}{-9} \\\\= \dfrac{\cancel{-9}\cdot7}{\cancel{-9}} \\\\= 7 .\end{array}
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