Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 1 - Introduction to Algebraic Expressions - 1.7 Multiplication and Division of Real Numbers - 1.7 Exercise Set: 56

Answer

$151,200$

Work Step by Step

To multiply integers, multiply the numbers normally. If the signs of the numbers are the same, the product is positive. If the signs of the numbers are different, the product is negative. Hence, the given expression, $ (-5)(-6)(-7)(-8)(-9)(-10) ,$ simplifies to \begin{array}{l}\require{cancel} (-5)(-6)(-7)(-8)(-9)(-10) \\\\= (30)(-7)(-8)(-9)(-10) \\\\= (-210)(-8)(-9)(-10) \\\\= (1680)(-9)(-10) \\\\= (-15120)(-10) \\\\= 151,200 .\end{array}
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