Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 1 - Introduction to Algebraic Expressions - 1.7 Multiplication and Division of Real Numbers - 1.7 Exercise Set - Page 58: 116



Work Step by Step

The given expression, $ -\dfrac{5}{12}\div\dfrac{15}{7} $, simplifies to \begin{array}{l}\require{cancel} -\dfrac{5}{12}\cdot\dfrac{7}{15} \\\\= \dfrac{-5(7)}{12(15)} \\\\= \dfrac{-\cancel{5}(7)}{12(\cancel{5}\cdot3)} \\\\= \dfrac{-7}{36} \\\\= -\dfrac{7}{36} .\end{array}
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