Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 1 - Introduction to Algebraic Expressions - 1.7 Multiplication and Division of Real Numbers - 1.7 Exercise Set - Page 58: 76

Answer

$-3$

Work Step by Step

The given expression, $ -3.9\div1.3 $, simplifies to \begin{array}{l}\require{cancel} \dfrac{-3.9}{1.3} \\\\= \dfrac{\cancel{1.3}\cdot(-3)}{\cancel{1.3}} \\\\= -3 .\end{array}
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