Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 1-4 - Cumulative Review: 4

Answer

$6$

Work Step by Step

The given expression, $ 2-[10-(5+12\div2^2\cdot3)] ,$ simplifies to \begin{array}{l} 2-[10-(5+12\div4\cdot3)] \\\\= 2-[10-(5+3\cdot3)] \\\\= 2-[10-(5+9)] \\\\= 2-[10-14] \\\\= 2-[-4] \\\\= 2+4 \\\\= 6 .\end{array}
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