Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 1-4 - Cumulative Review: 13

Answer

Refer to the graph below.
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Work Step by Step

Find the x-intercept by setting $y=0$ then solving for $x$: $3y-2x=12 \\3(0)-2x=12 \\-2x=12 \\\frac{-2x}{-2}=\frac{12}{-2} \\x=-6$ Thus, the x-intercept is $(-6, 0)$. Find the y-intercept by setting $x=0$ then solving for $y$: $3y-2x=12 \\3y-2(0)=12 \\3y=12 \\\frac{3y}{3}=\frac{12}{3} \\y=4$ Thus, the y-intercept is $(0, 4)$. Plot the intercepts then connect them using a line to complete the graph. (refer to the graph in the answer part above)
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