Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 1-4 - Cumulative Review - Page 301: 21



Work Step by Step

Distribute $4$ to obtain: $2-(x-7)=8-4(x)-4(5) \\2-(x-7)=8-4x-20 \\2-(x-7)=-4x-12$ $2-x-(-7)=-4x-12 \\2-x+7=-4x-12 \\9-x=-4x-12$ Add $4x$ to both sides to obtain: $9-x+4x=-4x-12+4x \\9+3x=-12$ Subtract $9$ to both sides of the equation to obtain: $9+3x-9=-12-9 \\3x=-21$ Divide $3$ to both sides of the equation: $\dfrac{3x}{3}=\dfrac{-21}{3} \\x=-7$
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