## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson

# Chapter 1-4 - Cumulative Review: 3

#### Answer

$-\dfrac{7}{45}$

#### Work Step by Step

The given expression, $\dfrac{1}{15}-\dfrac{2}{9} ,$ simplifies to \begin{array}{l} \dfrac{3}{45}-\dfrac{10}{45} \\\\= -\dfrac{7}{45} .\end{array}

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