Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 1-4 - Cumulative Review - Page 301: 14

Answer

Refer to the graph below.
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Work Step by Step

Solve for $y$ by dividing both sides of the equation by $3$: $\frac{3y}{3}=\frac{2}{3} \\y=\frac{2}{3}$ This means that equation $3y=2$ is equivalent to and has the same graph as $y=\frac{2}{3}$. RECALL: The graph of an equation of the form $y=k$ where $k$ is a real number is a horizontal line whose y-intercept is $(0, k)$. The line is parallel to the y-axis and each point on the line has a y-coordinate of $k$. Thus, the equation $y=\frac{2}{3}$ is a horizontal line whose y-intercept is $(0, \frac{2}{3})$. Every point on the line has a y-coordinate of $\frac{2}{3}$. This means the following points are on the line: $(0, \frac{2}{3})$, $(-2, \frac{2}{3})$, and $(2, \frac{2}{3})$ Plot the three points above then connect them using a line to complete the graph. (Refer to the graph in the answer part above.)
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