Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 1-4 - Cumulative Review - Page 301: 20



Work Step by Step

Add $1$ to both sides to obtain: $5y+7+1=8y-1+1 \\5y+8=8y$ Subtract $5y$ to both sides of the equation: $5y+8-5y=8y-5y \\8=3y$ Divide both sides by $3$ to obtain: $\dfrac{8}{3}=\dfrac{3y}{3} \\\dfrac{8}{3}=y$
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