Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 1-14 - Cumulative Review - Final Exam - Page 930: 7

Answer

$9a^4-30a^2y+25y^2$

Work Step by Step

Using $(a+b)^2=a^2+2ab+b^2$, or the special product of the square of a binomial, the given expression, $ (3a^2-5y)^2 ,$ is equivalent to \begin{align*}\require{cancel} & (3a^2)^2+2(3a^2)(-5y)+(-5y)^2 \\&= 9a^4-30a^2y+25y^2 .\end{align*} Hence, the expression $(3a^2-5y)^2$ is equivalent to $9a^4-30a^2y+25y^2$.
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