Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 1-14 - Cumulative Review - Final Exam - Page 930: 30

Answer

$5$ units

Work Step by Step

With the given points, $ (-1,-5) $ and $ (2,-1) ,$ we find: \begin{align*} x_1&= -1 \\x_2&= 2 \\y_1&= -5 \\y_2&= -1 .\end{align*} Using the Distance Formula: $d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2} $ \begin{align*} d&=\sqrt{(-1-2)^2+(-5-(-1))^2} \\&= \sqrt{(-1-2)^2+(-5+1)^2} \\&= \sqrt{(-3)^2+(-4)^2} \\&= \sqrt{9+16} \\&= \sqrt{25} \\&= 5 .\end{align*} Hence, the distance between $ (-1,-5) $ and $ (2,-1) $ is $5$ units.
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