Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 1-14 - Cumulative Review - Final Exam - Page 930: 45

Answer

$x=-\dfrac{1}{2}$

Work Step by Step

Expressing both sides of the given equation, $ 7^{2x+3}=49 ,$ with the same base gives: \begin{align*} 7^{2x+3}&=7^2 .\end{align*} Since the bases in the equation above are the same, the exponents can be equated. That is, \begin{align*}\require{cancel} 2x+3&=2 .\end{align*} Using the properties of equality, the equation above is equivalent to \begin{align*}\require{cancel} 2x+3-3&=2-3 \\ 2x&=-1 \\\\ \dfrac{\cancel2x}{\cancel2}&=-\dfrac{1}{2} \\\\ x&=-\dfrac{1}{2} .\end{align*} Hence, the solution to the equation $7^{2x+3}=49$ is $x=-\dfrac{1}{2}$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.