Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 1-14 - Cumulative Review - Final Exam - Page 930: 11

Answer

$12a^2\sqrt{b}$

Work Step by Step

Using $\sqrt{a}\cdot\sqrt{b}=\sqrt{ab},$ the given expression, $ \sqrt{12a}\sqrt{12a^3b} ,$ is equivalent to \begin{align*} & \sqrt{12a(12a^3b)} \\&= \sqrt{12^2a^4b} .\end{align*} Extracting the roots of the factors that are perfect powers of the index, the expression above is equivalent to \begin{align*}\require{cancel} & \sqrt{(12a^2)^2b} \\\\&= |12a^2|\sqrt{b} &(\text{use }\sqrt{x^2}=|x|) \\&= 12a^2\sqrt{b} &(\text{since }|12|=12,\text{ }|a^2|=a^2) .\end{align*} Hence, the expression $\sqrt{12a}\sqrt{12a^3b}$ simplifies to $12a^2\sqrt{b}$.
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