Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 1-14 - Cumulative Review - Final Exam - Page 930: 31

Answer

$a_{21}=-121$

Work Step by Step

Using $a_n=a_1+(n-1)d$ or the formula for the $n^{th}$ term of an arithmetic sequence, with $a_1=19$, $d=-7,$ and $n=21,$ then \begin{align*} a_{21}&=19+(21-1)(-7) \\&= 19+(20)(-7) \\&= 19-140 \\&= -121 .\end{align*} Hence, the $21^{st}$ term of $19,12,5,...,$ is $a_{21}=-121$.
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