Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 1-10 - Cumulative Review - Page 696: 9

Answer

$$z=-2,\:y=-1,\:x=1$$

Work Step by Step

Solving the system of equations using substitution, we find: $$ 5\cdot \frac{1+\frac{-z-7}{5}-z}{2}-\frac{-z-7}{5}+3z=0 \\ z=-2 \\ y=\frac{-\left(-2\right)-7}{5}=-1 \\ x=\frac{1-1-\left(-2\right)}{2}=1$$
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