Answer
$$x=0,\:x=-2$$
Work Step by Step
Isolating the variable using the rules of fractions, we find:
$$ \frac{2x+1}{\left(x+1\right)\left(1-x\right)}=1\\ 2x+1=\left(x+1\right)\left(1-x\right)\\ -x^2-2x=0\\ x=0,\:x=-2$$
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