# Chapter 1-10 - Cumulative Review - Page 696: 32

$$h=2\sqrt{3}$$

#### Work Step by Step

We draw a line straight through the middle of the triangle to form two right triangles. We see that the base of this right triangle will be 2 and its hypotenuse will be 4. Thus: $$h=\sqrt{4^2-2^2}\\\ h=\sqrt{12}\\ h=2\sqrt{3}$$

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