Answer
$$y^{\frac{8}{15}}$$
Work Step by Step
Simplifying the expression using the rules of radicals, we find:
$$ \sqrt[3]{y}\sqrt[5]{y}\\ y^{\frac{1}{3}+\frac{1}{5}}\\ y^{\frac{8}{15}}$$
Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)
by Bittinger, Marvin L.; Ellenbogen, David J.; Johnson, Barbara L.
Published by
Pearson
ISBN 10:
0-32184-874-8
ISBN 13:
978-0-32184-874-1
Chapter 1-10 - Cumulative Review - Page 696: 23
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