Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 1-10 - Cumulative Review - Page 696: 7

Answer

$$x=-3,\:x=2$$

Work Step by Step

Solving the equation by isolating the variable using the rules of Algebra, we find: $$ \frac{2x}{x-1}\left(x-1\right)\left(x-3\right)+\frac{x}{x-3}\left(x-1\right)\left(x-3\right)=2\left(x-1\right)\left(x-3\right)\\ 2x\left(x-3\right)+x\left(x-1\right)=2\left(x-1\right)\left(x-3\right)\\ x=-3,\:x=2$$
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