Answer
$$x=7$$
Work Step by Step
Solving the equation by isolating the variable using the rules of Algebra, we find:
$$ \left(\sqrt{2x-5}\right)^2=\left(x-4\right)^2\\\ 2x-5=x^2-8x+16\\ x=7$$
Note, $x=3$ is not a valid solution.
Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)
by Bittinger, Marvin L.; Ellenbogen, David J.; Johnson, Barbara L.
Published by
Pearson
ISBN 10:
0-32184-874-8
ISBN 13:
978-0-32184-874-1
Chapter 1-10 - Cumulative Review - Page 696: 8
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