Answer
$a+5-\dfrac{4}{a+3}$
Work Step by Step
Equating the divisor of the expression to 0 and then solving gives:
\begin{align*}
a+3&=0
\\
a&=-3
.\end{align*}
The last row of numbers, $\left\{
1,5,-4
\right\},$ gives the coefficient of the quotient and the remainder. Hence, $(
a^2+8a+11
)\div(
a+3
)
$ is equal to
\begin{align*}
a+5-\dfrac{4}{a+3}
.\end{align*}
