Answer
$2x^2-5x+3+\dfrac{8}{x+2}$
Work Step by Step
Equating the divisor of the expression to 0 and then solving gives:
\begin{align*}
x+2&=0
\\
x&=-2
.\end{align*}
The last row of numbers, $\left\{
2,-5,3,8
\right\},$ gives the coefficient of the quotient and the remainder. Hence, $(
2x^3-x^2-7x+14
)\div(
x+2
)
$ is equal to
\begin{align*}
2x^2-5x+3+\dfrac{8}{x+2}
.\end{align*}
