Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Appendix C - Synthetic Division and the Remainder Theorem - C Exercise Set - Page 992: 17

Answer

$x^4+2x^3+4x^2+8x+16$

Work Step by Step

Equating the divisor of the expression to 0 and then solving gives: \begin{align*} x-2&=0 \\ x&=2 .\end{align*} The last row of numbers, $\{ 1,2,4,8,16,0 \},$ represents the coefficients of the quotient and the remainder. Hence, $( x^5-32 )\div( x-2 )$ is equal to \begin{align*} x^4+2x^3+4x^2+8x+16 .\end{align*}
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