Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Appendix C - Synthetic Division and the Remainder Theorem - C Exercise Set - Page 992: 1

Answer

The given statement is true.

Work Step by Step

The remainder theorem says that $P\left( -5 \right)$ is the remainder when $P\left( -5 \right)$ is divided by $P\left( x \right)={{x}^{3}}+7{{x}^{2}}+3x+4$. The value of $P\left( -5 \right)$ can be evaluated by using synthetic division. The dividend is ${{x}^{3}}+7{{x}^{2}}+3x+4$ and the divisor is $x+5$. The constant term of the divisor 5 with the opposite sign is written to left. The coefficients of the dividend $1,7,3,4$ are written to the right. Evaluate the value of $\left( {{x}^{3}}+7{{x}^{2}}+3x+4 \right)\div \left( x+5 \right)$ using synthetic division as follows. $\begin{align} & \left. {\underline {\, -5 \,}}\! \right| \text{ 1 7 3 4} \\ & \text{ }\underline{\text{ }-5\text{ }-10\text{ 35}} \\ & \text{ 1 2 }-7\text{ 39} \\ \end{align}$
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