Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 7 - Algebraic Fractions - 7.1 - Simplifying Algebraic Fractions - Problem Set 7.1: 33

Answer

$\frac{(2n-1)}{(n-3)}$

Work Step by Step

Since the numerator consists of a trinomial, we use the rules of factoring trinomials in order to factor it. For the case of the denominator, we use the rule $a^{2}-b^{2}=(a+b)(a-b)$ to factor it. Then, we cancel out the resultant common factors in the numerator and the denominator: $\frac{2n^{2}+5n-3}{n^{2}-9}$ =$\frac{2n^{2}-1n+6n-3}{n^{2}-3^{2}}$ =$\frac{n(2n-1)+3(2n-1)}{(n+3)(n-3)}$ =$\frac{(2n-1)(n+3)}{(n+3)(n-3)}$ =$\frac{(2n-1)}{(n-3)}$
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